std::fma, std::fmaf, std::fmal - cppreference.com

Defined in header

<cmath>

floatfma(floatx,floaty,floatz);doublefma(doublex,doubley,doublez);longdoublefma(longdoublex,longdoubley,longdoublez); (1)(since C++11)
(until C++23)constexpr/* floating-point-type */fma(/* floating-point-type */x,/* floating-point-type */y,/* floating-point-type */z);(since C++23)floatfmaf(floatx,floaty,floatz); (2)(since C++11)
(constexpr since C++23)longdoublefmal(longdoublex,longdoubley,longdoublez); (3)(since C++11)
(constexpr since C++23)#define FP_FAST_FMA /* implementation-defined */ (4) (since C++11)#define FP_FAST_FMAF /* implementation-defined */ (5) (since C++11)#define FP_FAST_FMAL /* implementation-defined */ (6) (since C++11)

Additional overloads

Defined in header

<cmath>

template<classArithmetic1,classArithmetic2,classArithmetic3>/* common-floating-point-type */fma(Arithmetic1x,Arithmetic2y,Arithmetic3z); (A)(since C++11)
(constexpr since C++23)1-3) Computes x*y+z as if to infinite precision and rounded only once to fit the result type. The library provides overloads of std::fma for all cv-unqualified floating-point types as the type of the parameters x, y and z.(since C++23)

4-6) If the macro constants FP_FAST_FMA, FP_FAST_FMAF, or FP_FAST_FMAL are defined, the function std::fma evaluates faster (in addition to being more precise) than the expression x*y+z for double, float, and longdouble arguments, respectively. If defined, these macros evaluate to integer 1.

A) Additional overloads are provided for all other combinations of arithmetic types.

Parameters

x, y, z - floating-point or integer values Return value

If successful, returns the value of x*y+z as if calculated to infinite precision and rounded once to fit the result type (or, alternatively, calculated as a single ternary floating-point operation).

If a range error due to overflow occurs,

±HUGE_VAL

, ±HUGE_VALF, or ±HUGE_VALL is returned.

If a range error due to underflow occurs, the correct value (after rounding) is returned.

Error handling

Errors are reported as specified in

math_errhandling

.

If the implementation supports IEEE floating-point arithmetic (IEC 60559),

If x is zero and y is infinite or if x is infinite and y is zero, and if z is not a NaN, then NaN is returned and

FE_INVALID

is raised,

if z is a NaN, then NaN is returned and

FE_INVALID

may be raised.

If x*y is an exact infinity and z is an infinity with the opposite sign, NaN is returned and

FE_INVALID

is raised.

If x or y are NaN, NaN is returned.

If z is NaN, and x*y is not 0*Inf or Inf*0, then NaN is returned (without

FE_INVALID

).

Notes

This operation is commonly implemented in hardware as

fused multiply-add

CPU instruction. If supported by hardware, the appropriate FP_FAST_FMA? macros are expected to be defined, but many implementations make use of the CPU instruction even when the macros are not defined.

POSIX

(fma, fmaf, fmal)

additionally specifies that the situations specified to return

FE_INVALID

are domain errors.

Due to its infinite intermediate precision, std::fma is a common building block of other correctly-rounded mathematical operations, such as

std::sqrt

or even the division (where not provided by the CPU, e.g.

Itanium

).

As with all floating-point expressions, the expression x*y+z may be compiled as a fused multiply-add unless the

#pragma

STDCFP_CONTRACT is off.

The additional overloads are not required to be provided exactly as (A). They only need to be sufficient to ensure that for their first argument num1, second argument num2 and third argument num3:

If num1, num2 or num3 has type longdouble, then std::fma(num1,num2,num3) has the same effect as std::fma(static_cast<longdouble>(num1),
static_cast<longdouble>(num2),
static_cast<longdouble>(num3)).

Otherwise, if num1, num2 and/or num3 has type double or an integer type, then std::fma(num1,num2,num3) has the same effect as std::fma(static_cast<double>(num1),
static_cast<double>(num2),
static_cast<double>(num3)).

Otherwise, if num1, num2 or num3 has type float, then std::fma(num1,num2,num3) has the same effect as std::fma(static_cast<float>(num1),
static_cast<float>(num2),
static_cast<float>(num3)).

(until C++23)If num1, num2 and num3 have arithmetic types, then std::fma(num1,num2,num3) has the same effect as std::fma(static_cast</*common-floating-point-type*/>(num1),
static_cast</*common-floating-point-type*/>(num2),
static_cast</*common-floating-point-type*/>(num3)), where /*common-floating-point-type*/ is the floating-point type with the greatest

floating-point conversion rank

and greatest

floating-point conversion subrank

among the types of num1, num2 and num3, arguments of integer type are considered to have the same floating-point conversion rank as double.

If no such floating-point type with the greatest rank and subrank exists, then

overload resolution

does not result in a usable candidate from the overloads provided.

(since C++23)Example

Run this code

#include<cfenv>#include<cmath>#include<iomanip>#include<iostream>#ifndef __GNUC__#pragma STDC FENV_ACCESS ON#endifintmain(){// demo the difference between fma and built-in operatorsconstdoublein=0.1;std::cout<<"0.1 double is "<<std::setprecision(23)<<in<<" ("<<std::hexfloat<<in<<std::defaultfloat<<")\n"<<"0.1*10 is 1.0000000000000000555112 (0x8.0000000000002p-3), "<<"or 1.0 if rounded to double\n";constdoubleexpr_result=0.1*10-1;constdoublefma_result=std::fma(0.1,10,-1);std::cout<<"0.1 * 10 - 1 = "<<expr_result<<" : 1 subtracted after intermediate rounding\n"<<"fma(0.1, 10, -1) = "<<std::setprecision(6)<<fma_result<<" ("<<std::hexfloat<<fma_result<<std::defaultfloat<<")\n\n";// fma is used in double-double arithmeticconstdoublehigh=0.1*10;constdoublelow=std::fma(0.1,10,-high);std::cout<<"in double-double arithmetic, 0.1 * 10 is representable as "<<high<<" + "<<low<<"\n\n";// error handlingstd::feclearexcept(FE_ALL_EXCEPT);std::cout<<"fma(+Inf, 10, -Inf) = "<<std::fma(INFINITY,10,-INFINITY)<<'\n';if(std::fetestexcept(FE_INVALID))std::cout<<" FE_INVALID raised\n";}Possible output:

0.1 double is 0.10000000000000000555112 (0x1.999999999999ap-4) 0.1*10 is 1.0000000000000000555112 (0x8.0000000000002p-3), or 1.0 if rounded to double 0.1 * 10 - 1 = 0 : 1 subtracted after intermediate rounding fma(0.1, 10, -1) = 5.55112e-17 (0x1p-54) in double-double arithmetic, 0.1 * 10 is representable as 1 + 5.55112e-17 fma(+Inf, 10, -Inf) = -nan FE_INVALID raised See also