std::nearbyint, std::nearbyintf, std::nearbyintl - cppreference.com

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Defined in header

<cmath>

floatnearbyint(floatnum);doublenearbyint(doublenum);longdoublenearbyint(longdoublenum); (1)(until C++23)/*floating-point-type*/nearbyint(/*floating-point-type*/num);(since C++23)floatnearbyintf(floatnum); (2)(since C++11)longdoublenearbyintl(longdoublenum); (3)(since C++11)

SIMD overload

(since C++26)

Defined in header

<simd>

template</*math-floating-point*/V>constexpr/*deduced-simd-t*/<V>nearbyint(constV&v_num); (S) (since C++26)

Additional overloads

(since C++11)

Defined in header

<cmath>

template<classInteger>doublenearbyint(Integernum); (A)1-3) Rounds the floating-point argument num to an integer value in floating-point format, using the

current rounding mode

. The library provides overloads of std::nearbyint for all cv-unqualified floating-point types as the type of the parameter.(since C++23)

A) Additional overloads are provided for all integer types, which are treated as double.

(since C++11)Parameters

num - floating-point or integer value Return value

The nearest integer value to num, according to the

current rounding mode

, is returned.

Error handling

This function is not subject to any of the errors specified in

math_errhandling

.

If the implementation supports IEEE floating-point arithmetic (IEC 60559),

FE_INEXACT

is never raised.

If num is ±∞, it is returned, unmodified.

If num is ±0, it is returned, unmodified.

If num is NaN, NaN is returned.

Notes

The only difference between std::nearbyint and

std::rint

is that std::nearbyint never raises

FE_INEXACT

.

The largest representable floating-point values are exact integers in all standard floating-point formats, so std::nearbyint never overflows on its own; however the result may overflow any integer type (including

std::intmax_t

), when stored in an integer variable.

If the current rounding mode is

FE_TONEAREST

, this function rounds to even in halfway cases (like

std::rint

, but unlike

std::round

).

The additional overloads are not required to be provided exactly as (A). They only need to be sufficient to ensure that for their argument num of integer type, std::nearbyint(num) has the same effect as std::nearbyint(static_cast<double>(num)).

Example

Run this code

#include<cfenv>#include<cmath>#include<iostream>#pragma STDC FENV_ACCESS ONintmain(){std::fesetround(FE_TONEAREST);std::cout<<"rounding to nearest: \n"<<"nearbyint(+2.3) = "<<std::nearbyint(2.3)<<" nearbyint(+2.5) = "<<std::nearbyint(2.5)<<" nearbyint(+3.5) = "<<std::nearbyint(3.5)<<'\n'<<"nearbyint(-2.3) = "<<std::nearbyint(-2.3)<<" nearbyint(-2.5) = "<<std::nearbyint(-2.5)<<" nearbyint(-3.5) = "<<std::nearbyint(-3.5)<<'\n';std::fesetround(FE_DOWNWARD);std::cout<<"rounding down:\n"<<"nearbyint(+2.3) = "<<std::nearbyint(2.3)<<" nearbyint(+2.5) = "<<std::nearbyint(2.5)<<" nearbyint(+3.5) = "<<std::nearbyint(3.5)<<'\n'<<"nearbyint(-2.3) = "<<std::nearbyint(-2.3)<<" nearbyint(-2.5) = "<<std::nearbyint(-2.5)<<" nearbyint(-3.5) = "<<std::nearbyint(-3.5)<<'\n';std::cout<<"nearbyint(-0.0) = "<<std::nearbyint(-0.0)<<'\n'<<"nearbyint(-Inf) = "<<std::nearbyint(-INFINITY)<<'\n';}Output:

rounding to nearest: nearbyint(+2.3) = 2 nearbyint(+2.5) = 2 nearbyint(+3.5) = 4 nearbyint(-2.3) = -2 nearbyint(-2.5) = -2 nearbyint(-3.5) = -4 rounding down: nearbyint(+2.3) = 2 nearbyint(+2.5) = 2 nearbyint(+3.5) = 3 nearbyint(-2.3) = -3 nearbyint(-2.5) = -3 nearbyint(-3.5) = -4 nearbyint(-0.0) = -0 nearbyint(-Inf) = -inf See also